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The annihilation mass of an electron is always primary in relation to its inert mass, which is expressed in relation to the energies of the electric and gravitational fields.
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The annihilation mass of an electron is always primary in relation to its inert mass, which is expressed in relation to the energies of the electric and gravitational fields.
E/M-FIELD OF ATOMIC ELECTRON
A moving electron has an electrical impulse pе = e × v, where pe and v are vector physical quantities. This same electron also has its own mechanical impulse.
P. K 57
The electric momentum of an electron is a vector quantity that has not only a direction, but also a sign of a charge. (K 2. 3) K 57
A single electrical impulse of an electron can be expressed as the product of the magnitude of its charge and the magnitude of its velocity (m / s)
p –e = m –e × v [C × m / s]
The same impulse p –e, but existing in a closed conductor, can always be represented as a direct source of electric current iе. Consider an electron - e of a hydrogen atom moving in a stable orbit with a Bohr radius r1 = 0. 53 × 10 -10 m. Since this orbit is stable, there is an equality of the force of the Coulomb attraction of an electron by a nucleus with the centrifugal force of its mechanical motion in a given orbit.
1 e2 = me0 v2 .
4pe0 r12 r1
Where: v is the speed of an electron in a given orbit.
Using the Coulomb law, we calculate the value of the electric field strength En, created by the electric charge of the nucleus of the hydrogen atom, at a distance of the radius r1 of the electron orbit.
En = 1 × e+ = 1 V × m × 1, 60 × 10-19 C = 5, 1 × 10 11 V/ m.
4pe0 r12 4 × 3. 14 × 8, 85 × 10 – 12 C (0. 53× 10 -10 m)2
The potential of this field jn = Eп × r1 = 5, 12 × 10 11 В × 0. 53 × 10 -10 м = 27, 1 V .
Let's calculate the value of the potential energy of the system of interacting charges.
U = - 1 e2 = 1 V × m × (1, 60 × 10-19C)2 = - 4, 3 × 10 -18 J.
4pe0 r 1 4 × 3. 14 × 8, 85 × 10 – 12 C 0. 53× 10 -10 m
Same: U = - 4, 3 × 10 -18 J = 26, 9 e V. (1 e V = 1, 60 -19 J)
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1, 60 -19 J/ e V
Same: U =jп × e = 27, 1 e V × 1, 60 × 10-19 C = - 4, 3 × 10 -18 J.
Let's calculate the value of the force of attraction between the electron and theproton.
F= En × e -- = 5, 1 × 10 11 V × 1, 60 × 10 --19 C = 8, 2 × 10 --8 Н.
m
The equilibrium of this system exists only at a certain speed of the electron.
v = Ö F r1 = Ö 8, 2 × 10 --8 Н × 0. 53 × 10 -10 m = 2, 2 × 10 6 m/s.
me 9. 11× 10 —31 kg
In this orbit, the electron moves at a speed vе = 2, 2 × 10 6 m/s and frequency fе = 7 × 10 15 1/s. Thus, it creates a circular electric current iе = efе = 1. 62 × 10 -19 C× 7 × 10 15 s-1 = 1, 1 × 10 -3 a. (1 a = 1 C/s)
Now you can calculate the values of the mechanical ( p0e) and electrical (p–e) impulses of the electron.
p0e = me0 v = 9. 11× 10 -31 kg × 2, 2 × 10 6 m/s = 2, 0 × 10 -24 kg m/s.
p–e = m –e v = 1. 62 × 10 -19 C × 2, 2 × 10 6 m/s = 3, 55 × 10 -13 C m/s.
It is clear that this is one and the same impulse, but expressed in different dimensions, since it is always possible to express the charge of an electron by its annihilation mass, and its mass - by its annihilation mass (charge). The ratio of the electron charge to its inert mass (specific charge of the electron) is k Q/M = - e / me = 1, 7588 10 11 C/kg. Note that this is, in fact, dimensionless coefficient, since the mass and mass of the annihilation of an electron are always the same.
p0e = p–e = 3, 55 × 10 -13 C m/s = 2, 0 × 10 -24 kg m/s.
k Q/M = 1, 76 10 11 C/kg
But the inert mass of the electron here has absolutely nothing to do with the appearance of the magnetic field, since it is not a continuation of the gravitational field.
Consider the ratio of the electric impulse of the electron and the current corresponding to it (1 a = 1 C / s).
p-e = 3, 55 × 10 -13 C m/s= 3, 3 10 -10 m.
iе 1, 1 × 10 -3 C/s
Which is equal to the length of the orbit of this electron (2 × 3. 14 × 0. 53× 10 -10 m = 3, 3 10 -10 m).
In fact, so an electrical impulse is a specific entity, and the electrical current of this impulse is only its physical parameter.
P. К 58
The electrical impulse of a moving charge is always and necessarily the direct cause of the electric current created by it, but not vice versa. (К 2. 3) К 58
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For a physicist, this may not be so important, but for a philosopher it is very important not to confuse an object with its quantity. Here the object is an electrical impulse, and its quantity is the magnitude of the electric current it creates. In addition, physics has established the fundamental quantity of electricity to be electric current, and not the charge that creates it. And this is already wrong, because the electric charge is primary in the phenomenon of electric current.
Now, based on the knowledge of the magnitude of the current that created the considered electrical impulse, it is possible to calculate the intensity of the magnetic induction Be. magnetic field within the orbit of a given electron.
Ве = mо × i = 12, 57 × 10 -7 V × s 2 × 1, 1 × 10 -3 a = 13, 1 Т.
2rе C × m 2 × 0. 53 × 10 -10 m
Where mо = 12, 57× 10 -7 Hn /m is the magnetic constant for vacuum. The unit of intensity of magneticinduction (B) is tesla (T).
Т = Hn × a = Ω × s × a = V × s = Wb.
m m m m m2 m2
The magnetic flux Ф passing through the area S, perpendicular to the vector of magnetic induction B, in a uniform field is equal to the product of the magnetic induction and the size of the area. Ф = В × S. The unit of measurement of the magnetic flux Ф is weber (Wb),
где Wb = Т × m 2 = V × s × m 2 = V× s.
m2
The total flux of magnetic induction created by the electron Фе = Ве × Sе, in this case, it passes through the area S bounded by the electron orbit.
Sе = 3, 14 × (0. 53 × 10 -10 m )2 = 0, 88 × 10 -20 m 2.
Фе = 13. 1 Т × 0, 88 × 10 -20 m 2 = 1, 15 × 10 -19 V × s.
For greater clarity of this field, you can change its dimension.
Wb = Т × m2 = В × с × m 2 = V × s = C × s .
m 2 m
In ordinary space, there is an electrical impulse.
p–e = 3, 55 × 10 -13 C × m/s,
and in hyperspace there is a specular " reflection" of this impulse in the form of the total flux of its magnetic field.
Фе =1, 15 × 10 -19 C × s/m.
The ratio of the magnetic field of the electric impulse to the magnitude of this impulse is equal to the magnitude of the magnetic coefficient kM.
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